Table of Contents

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Polar form!

We do polar form because its easier to do multiplication and division when compared to addition and subtraction in rect form.

A "natural" form of expressing complex number, multiplication, division, raising to powers.

Something something rect form is translations relative to i and j components, i.e. x and y axis respectively (i.e. real and imaginary axis respectively)

Geometry of multiplication of comple numbers

Consider $(2+i)\times (-3+2i)$.

When you plot them out, you notice that the angle made by the product is the sum of the angles of the two complex numbers, and the magnitude of the product is the sum of the magnitudes of the two complex number. and the product of the magnitudes of the two complex numbers.

(plot twist this is polar form)

Something something you can multiply by specific complex numbers which relate to a rotation by a certain angle.

Hence, there is a geometric interpretation of complex number multiplication. When multiplying by a complex number $z$ the things determining the corresponding geometric transfomrations are

This suggest that a way of representing $z$ where $|z| \text{ and }\theta$ are very explicit.

Hence, polar form!

Rewriting

how to rewrite $z=a+bi$ so that $|z|$ and $\theta$ are explicit.

$$\begin{align} |z| &= \sqrt{ a^{2}+b^{2} } \\ \cos \theta &= \frac{a}{|z|} , \text{ so } a=|z|\cos \theta. \\ \text{Similarly, } \sin \theta&=\frac{b}{|z|} , \text{ so } b=|z|\sin \theta \\ z &\implies |z|(\cos \theta+i\sin \theta) \end{align} $$

This is the polar form!!!

Hence, try to rewrite $z=\frac{5}{\sqrt{ 2 }}+\frac{5}{\sqrt{ 2 }}i$. $|z| = \sqrt{ \frac{25}{2}+\frac{25}{2} }=5$ and argument = $\frac{\pi}{4}$

Hence, $z=5\left( \cos\left( \frac{\pi}{4} \right)+i\sin\left( \frac{\pi}{4} \right) \right)$

(Shorthand for this is $z=5cis\left( \frac{\pi}{4} \right)$)

Formal definition of polar form

The polar form of a complex number $z$ is:

$$|z|(\cos \theta + i \sin \theta) $$

Where:

Practice

General method:

  1. Evaluate $\tan^{-1}\left( \frac{b}{a} \right)$.
  2. If necessary, add or subtract $\pi$ to ensure that:
    • $\theta$ describes the complex number
    • $-\pi < \theta \leq \pi$
$$\begin{align} 5cis\left( -\frac{3\pi}{4} \right)&=5\left( -\frac{1}{\sqrt{ 2 }} \right)+5i\left(-\frac{1}{\sqrt{ 2 }}\right) \\ &= -\frac{5}{\sqrt{ 2 }}-\frac{5}{\sqrt{ 2 }}i \end{align} $$