Table of Contents

Graph

Charged particles in E and B field

Before relativity in electric fields

$$\begin{align} W=Vq \\ F=qE \\ E=\frac{V}{d} \\ qV=\frac{1}{2}mv^2 \end{align} $$

Hence, when we place a charged particle in an electric field, it is accelerated, and gains kinetic energy(work is done on it).

Note, this can be very fast. Consider having to use $Vq=mc^2\left(\frac{1}{\sqrt{ 1-\frac{v^2}{c^2} }}-1 \right)$ to accurately determine the kinetic energy of the particle.

Hence, we can also use electric fields to change the direction of particles. Note, this is a parabolic trajectory (woops, no $r=\frac{mv}{qB}$)

Magnetic fields

Remember, $F=qvB\sin \theta$

This time, the direction is circular.

Velocity selector

Here, the magnetic force is upwards, the electric force is downwards. insert some math $v=\frac{E}{B}$

Cathode Ray Tube

Linear accelerator (LINAC)

Mass spectrometer

Why heavy deflected less:

$$\begin{align} qvB=\frac{mv^2}{r} \\ r=\frac{mv}{qB} \end{align} $$

So for heavier things, $m\uparrow$ $\implies$$r \uparrow$, hence it has a greater arc and appears to be deflected less :)

Cyclotron

$$\begin{align} qvB=\frac{mv^2}{r} \\ v=\frac{qBr}{m} \\ \frac{2\pi r}{T}=\frac{qbR}{m} \\ f=\frac{1}{T}=\frac{qB}{2\pi m} \end{align} $$

i.e. the frequency of a charged particle of fixed mass moving in circular motion through the cyclotron is constant!

A problem (with cyclotrons)

These things be going really fast. But with relativity, velocity and momentum change. This means that $f$ is no longer constant! Uh oh, things start to mess up. (Fail at 1% speed of light)

Synchrotron

We can harness the electron's energy to produce electromagnetic radiation of various frequencies.

When electrons lose energy (or oscillate) they emit electromagnetic radiation.